Activity for Snoopy‭

Type	On...	Excerpt	Status	Date
Comment	Post #285036	@#8046 That's a long story. Basically, on Math SE, there is a small group of people who dominate the "deletion queue" of the site in a chat room. They have a very strong opinions on what kind of questions should not be allowed. Whenever they think the posts are not "good questions" using their st... (more)	—	over 2 years ago
Comment	Post #285036	"What draws newcomers in?" Many good contributors suffer from (a lot of) their valuable highly upvoted answers being deleted frequently by a clique in Math Stack Exchange. Some of them have stopped doing any further contributions on that site. Those are some potential users of codidact. (more)	—	over 2 years ago
Edit	Post #286788	Post edited:	—	over 2 years ago
Edit	Post #286788	Initial revision	—	over 2 years ago
Question	—	The gcd of powers in a gcd domain Question: $\def\gcd{\operatorname{gcd}}$Let $R$ be a gcd domain. Does it always hold that $\gcd(x^m,y^m)=\gcd(x,y)^m$? Context. If the ring is a Bezout domain, then we can apply this method. However, a gcd domain may not be a Bezout domain. I don't know how I can go on. (more)	—	over 2 years ago