Activity for Bennyshinichiâ€
Type | On... | Excerpt | Status | Date |
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Edit | Post #291497 | Initial revision | — | about 8 hours ago |
Question | — |
How to find a point on a vector equation with another vector equation and perpendicular distance? Given two lines, $l: 3x-y=9$ and $m: x-3y=3$, and an angle bisector $x-y=3$. Point $A\left(3,0\right)$ is where these three lines intersect. The problem asks us to find a point on the angle bisector that is at a perpendicular distance of $\sqrt{10}$ from line $m$. I know that we can use the distance ... (more) |
— | about 8 hours ago |