Activity for Hudjefa
Type | On... | Excerpt | Status | Date |
---|---|---|---|---|
Comment | Post #292215 |
Firstly, gracias for the answer.
What kind of *additional information* would be required? Is there some way to reduce the number of steps (the lost object *is* in one of the $4$ squares) to discovery of the lost object?
How about if I *randomly* (???) sweep sections of the $3$ squares left. Div... (more) |
— | 4 months ago |
Edit | Post #292224 |
Post edited: |
— | 4 months ago |
Edit | Post #292224 |
Post edited: |
— | 4 months ago |
Edit | Post #292224 | Initial revision | — | 4 months ago |
Answer | — |
A: Search & Probability (more) |
— | 4 months ago |
Comment | Post #292207 |
As you can see, the probabilities $P(F)$ do get *updated* post a null search result, but it doesn't provide clues as to which of the next squares to search. (more) |
— | 5 months ago |
Edit | Post #292207 | Initial revision | — | 5 months ago |
Question | — |
Search & Probability Search Grid Above is a $2 \times 2$ search grid constructed to search for a lost object. We begin by not knowing anything and hence if F = finding the object in a particular square, $P(F) = \frac{1}{4}$. Figure A. We check $1$ square and we don't find the object (that's figure B with one sq... (more) |
— | 5 months ago |
Edit | Post #290581 |
Post edited: |
— | 11 months ago |
Edit | Post #290581 |
Post edited: |
— | 11 months ago |
Edit | Post #290581 | Initial revision | — | 11 months ago |
Answer | — |
A: Strange behavior in elections and pie charts My approach is, I suppose, simpler. There are 4 voters: A, B, C, D. They vote randomly There are 4 candidates vying for A, B, C, D's attention. Let's call them W, X, Y, Z How many different possible electorate results are there? 1 candidate gets all 4 votes: $^4C1 = 4$ 1 candidate gets... (more) |
— | 11 months ago |
Edit | Post #290230 |
Post edited: |
— | about 1 year ago |
Edit | Post #290230 |
Post edited: |
— | about 1 year ago |
Edit | Post #290230 |
Post edited: |
— | about 1 year ago |
Edit | Post #290230 |
Post edited: |
— | about 1 year ago |
Edit | Post #290230 |
Post edited: |
— | about 1 year ago |
Edit | Post #290230 | Initial revision | — | about 1 year ago |
Answer | — |
A: How can school children intuit why over 100, D is larger? But under 100, D% is larger? If cost is $c$, sold for $s$, discount, $d = c - s$ Discount percentage = $\frac{c - s}{c} \times 100 = (c - s)\times \frac{100}{c}$ Absolute discount = $c - s$ As you can see ... 1. When $c 1$, and so, $(c - s)\times \frac{100}{c} > (c - s)$. The percentage discount > The absolute... (more) |
— | about 1 year ago |
Edit | Post #290229 | Initial revision | — | about 1 year ago |
Answer | — |
A: Is there a statistical method to identify the type of outliers shown in the pictures attached to my question? A value $x$ is an outlier IFF 1. $x Q3 + 1.5(IQR)$ where $Q1$ is the lower quartile, $Q3$ is the upper quartile, and $IQR = Q3 - Q1$, the interquartile range. (more) |
— | about 1 year ago |
Edit | Post #289783 |
Post edited: |
— | about 1 year ago |
Edit | Post #289783 | Initial revision | — | about 1 year ago |
Answer | — |
A: Solely by eye, how can 16 year olds visually distinguish $\color{red}{\vec{b} - \vec{r}}$ from $\color{limegreen}{|\vec{b}| - |\vec{r}|}$ ? You need to: 1. Explain what a scalar is (pure magnitude) 2. Explain what a vector is (magnitude & direction). As you've drawn the diagram, your intention is clear. $\vec b - \vec r$ (in red) has been labelled (in)correctly (no arrows over b and r). You also wish to emphasize that $|\vec b| -... (more) |
— | about 1 year ago |
Comment | Post #289712 |
The minimum sample size is 30. Anything less than that and your sample is no good (too small). However, the *unbiased variance* applies to all samples less than the population size. (more) |
— | about 1 year ago |
Edit | Post #289711 |
Post edited: |
— | over 1 year ago |
Edit | Post #289712 | Initial revision | — | over 1 year ago |
Answer | — |
A: What is the formula for sample standard deviation of a small sample size? From the little that I know ... 1. If the sample = population (census) $\sigma^2 = \displaystyle\frac{1}{N}\sum{i = 1}^N (xi - \mu)^2$ where $N$ is the size of the population and $\mu$ is the population mean. The variance is $\sigma^2$ and the standard deviation then is $\sigma$ 2. If the ... (more) |
— | over 1 year ago |
Edit | Post #289711 | Initial revision | — | over 1 year ago |
Answer | — |
A: 25% probability that there was a chance of avoiding injury $\quad$ vs. $\quad$ 25% chance of avoiding injury My two cents ... for what they're worth. Imagine someone places 4 identical boxes (A, B, C, D) in front of you. All of the boxes contain 4 identical cups of coffee each (4 × 4 = 16 cups of coffee that are indistinguishable from each other). In 3 of the boxes all the cups are laced with poison (inj... (more) |
— | over 1 year ago |