Activity for Moshi‭

Type	On...	Excerpt	Status	Date
Comment	Post #287819	This one? https://math.stackexchange.com/questions/498393/finding-an-integer-coefficients-quadratic-equation-which-has-approximate-solutio (more)	—	over 1 year ago
Comment	Post #287410	In your post, your equation includes a +1 term, while your general form in the title doesn't. I haven't tried solving it yet to see whether either is a square, but which one is intended? Secondarily, could you put the general form into the body of the post? (more)	—	over 1 year ago
Comment	Post #287188	Putting aside the fact that math does not particularly care about physical possibilities, and further the fact that it isn't physically impossible to trisect an object.... The existence of a repetend (aka repeated digits) depends completely on what base we use. Consider for a moment the usage of b... (more)	—	over 1 year ago
Comment	Post #287078	Wikipedia has an explanation that is pretty similar to my understanding: https://en.m.wikipedia.org/wiki/Precalculus In my experience, it generally consists of -an introduction to trigonometry -an introduction to proofs -an introduction to (infinite) series and products, and limits Wit... (more)	—	over 1 year ago
Comment	Post #283387	@#53628 I'm not sure what you're asking. Asking why it's defined like that is like asking why the sum of x and y is denoted x+y; it's done so by convention. I'm any case, it wouldn't make sense the other way around. We defined A as the event of prior abuse, G as the event of guilt, and M as the ev... (more)	—	over 2 years ago
Comment	Post #283387	By definition, the proportion of men who abuse their wives given that they are guilty of murdering them is P(A|G,M), and similarly for the other one. (more)	—	over 2 years ago
Comment	Post #283281	@#36363 Mathematical perimeters do not have a concept of width, since they are one dimensional. What you're describing is an [annulus](https://en.m.wikipedia.org/wiki/Annulus_(mathematics)). (more)	—	over 2 years ago
Comment	Post #283281	@#36363 When you do `border: 2px solid black`, you make it 2px *thick*. The *length* of the perimeter would not be 2px. The Greek letter there is pi, https://en.wikipedia.org/wiki/Pi (more)	—	over 2 years ago
Comment	Post #283281	Are you looking for an answer other than "The perimeter of a circle is given by $2\pi r$"? Because most common shapes already have formulas for their perimeter. (And for arbitrary parameterized shapes you can just use a line integral, which is basically another fomula) (more)	—	over 2 years ago
Comment	Post #283260	You made a mistake in your calculations, $$(1:999)(99:1)=(99:999)=(11:111)\ne(1:111)$$ Using $(11:111)$ gives the expected result of <span>$\frac{11}{122}\approx 0.09016$ (more)	—	over 2 years ago
Comment	Post #283123	$x^2+y^2=5$ is the equation of a circle (of radius $\sqrt5$) (more)	—	over 2 years ago
Comment	Post #278772	@#54204 https://github.com/mathjax/MathJax/issues/2312 MathJax 3 (what Codidact is using) has issues with `\\`. For now, you can wrap them in an environment such as `\displaylines`, e.g. ``` <p>$$\displaylines{123 \\\ 321}$$</p> ``` Don't ask me why \displaylines uses three backslashes... (more)	—	over 2 years ago
Comment	Post #278772	@#54204 It's already there :) (more)	—	over 2 years ago
Comment	Post #278772	@#54204 Try wrapping it in a `<p>` tag ``` <p>$$\begin{array}{l} P \text { (both girls, at least one winter girl })&=P \text { (both girls, at least one winter child) }\\ &=(1 / 4) P(\text { at least one winter child }) \\ &=(1 / 4)(1-P(\text { both are non-winter })) \\ &=(1 / 4)\left(1-(3 / 4)^... (more)	—	over 2 years ago
Comment	Post #278772	<p>$$\begin{array}{l} P \text { (both girls, at least one winter girl })&=P \text { (both girls, at least one winter child) }\\ &=(1 / 4) P(\text { at least one winter child }) \\ &=(1 / 4)(1-P(\text { both are non-winter })) \\ &=(1 / 4)\left(1-(3 / 4)^{2}\right) \end{array}$$</p> (more)	—	over 2 years ago
Comment	Post #278772	@#54204 Could you post what you're trying? (Preferably in a new thread) I'll try to see what's wrong. (more)	—	over 2 years ago
Comment	Post #282343	@#8056 It was fixed literally the next day lol (https://math.codidact.com/posts/278672) (more)	—	almost 3 years ago
Comment	Post #282060	Could you elaborate why you think it would be (true positives/false positives)? By analogy, say we have an 11-sided dice roll, with 11 being a true positive and 1-10 being false positive. Clearly, the probablity of landing a 1 is *not* 1/10, but 1/11. (more)	—	almost 3 years ago
Comment	Post #280856	I'd also like to add that not everyone is necessarily fluent in LaTeX, and I don't think we should expect everyone to be. If someone *really* doesn't like people posting screenshots of equatons, then they should suggest an edit themselves to convert it into LaTeX. (more)	—	about 3 years ago
Comment	Post #280742	This is a known bug (https://math.codidact.com/posts/278763), I suggested a quick workaround which should fix the issue until the renderer is fixed (more)	—	about 3 years ago
Comment	Post #280068	On the other hand, I think of $1/\sqrt3$ as 'simpler' in that it is just the reciprocal of root three, as opposed to being root three divided by three. (more)	—	over 3 years ago
Comment	Post #279225	`$Mathematics` lol https://math.codidact.com/help/how-to-ask (more)	—	over 3 years ago
Comment	Post #278772	@wizzwizz4 KaTeX is great, but it sadly still isn't as good as MathJax in terms of features. If you want though, you could make a new meta post to discuss that change (more)	—	over 3 years ago
Comment	Post #278772	@wizzwizz4 Maybe? The parser Codidact uses wasn't meant for latex and so doesn't have that sort of ability. (more)	—	over 3 years ago
Comment	Post #278724	@msh210 Edge on Windows 10 (more)	—	over 3 years ago
Comment	Post #278174	Could you clarify what you mean by HTML title? (more)	—	over 3 years ago