Activity for JRN
Type | On... | Excerpt | Status | Date |
---|---|---|---|---|
Comment | Post #286926 |
Do they have to be first order ordinary differential equations? (more) |
— | over 1 year ago |
Comment | Post #285983 |
The handwritten text that you show is not Xi, it is Xi divided by overline Xi (as shown in Peter Taylor's answer). (more) |
— | about 2 years ago |
Comment | Post #284723 |
"*In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator.*" If so, then your proposed method "$(a\times b)-(b-a)$" would involve addition, because it is just $a\times b-b+a$. (more) |
— | over 2 years ago |
Comment | Post #283252 |
From the words in the text "by putting the cutoff for a positive result at a very low level (purple dashed line), you may capture all positive samples, and so the test is very sensitive." and the words in the image "To increase sensitivity, shift to the left (blue line)," it can be concluded that the... (more) |
— | over 2 years ago |
Comment | Post #283945 |
You say "Solve all operations" but it seems that you mean "perform all operations." Instead of "equation solving," it seems that you are interested in "expression evaluation." For example, when you evaluate the expression "4(3+2)" as "20," you are not solving any equations (the expression does not ... (more) |
— | over 2 years ago |
Comment | Post #283633 |
What is the result of a vector crossed with itself? (more) |
— | over 2 years ago |
Comment | Post #283593 |
@#53922 A function can be a continuous function and yet still have a discontinuity at a point, as long as that point is not in its domain. (more) |
— | over 2 years ago |
Comment | Post #283593 |
The graph of Desmos is correct. But the function is still a continuous function. Desmos "doesn't say" it is a continuous function, but it "doesn't say" that it is not a continuous function, either. (more) |
— | over 2 years ago |
Comment | Post #283593 |
More specifically, while $f(x)=\frac{1}{x-1}$ is discontinuous at $x=1$, it is a continuous function because of what @r~~ said. (more) |
— | over 2 years ago |
Comment | Post #283317 |
@#54138 means the exponent must be zero, so it should be k (which is equal to zero) and it should not be k+1 (which is equal to one). (more) |
— | over 2 years ago |
Comment | Post #283281 |
A line has length but it has no thickness. When you say "measure a perimeter," that means measuring its length. You don't need to measure its "thickness" because the "thickness" of a line is zero. I suggest that you edit your question to say that you are interested in the "thickness" because the t... (more) |
— | over 2 years ago |
Comment | Post #283281 |
Based on your comments, it seems that you are asking about the "thickness" of the perimeter, and not its length. Is that correct? Are you basically asking how "thick" a line is? (more) |
— | over 2 years ago |
Comment | Post #283086 |
This is the first link that comes up when I use DuckDuckGo to search for "integration under integral sign": https://mathworld.wolfram.com/IntegrationUndertheIntegralSign.html (more) |
— | almost 3 years ago |
Comment | Post #282998 |
Please edit your question to use the correct term. (more) |
— | almost 3 years ago |
Comment | Post #282998 |
Do you perhaps mean that $x$ is a dummy *variable*? (more) |
— | almost 3 years ago |
Comment | Post #282702 |
See, for example, https://pwg.gsfc.nasa.gov/stargaze/Strig5.htm (more) |
— | almost 3 years ago |
Comment | Post #282623 |
Without context, it is difficult to answer your question. How are $f$ and $F$ related? Is $0\<\theta\<1$? Is $a\<b$? Is $h\>0$? (more) |
— | almost 3 years ago |
Comment | Post #282623 |
I asked you to identify the book so I can look up the context, what was before and what was after the text you quoted. But your answer does not identify the book (you didn't state the author, publisher, or year of publication). Perhaps if you showed an image of the page of the book in question, the... (more) |
— | almost 3 years ago |
Comment | Post #282623 |
From what book is this? (more) |
— | almost 3 years ago |
Comment | Post #282602 |
As it currently stands, your first question is inconsistent with what is in your image. (more) |
— | almost 3 years ago |
Comment | Post #282600 |
Also asked at https://matheducators.stackexchange.com/q/21150/77 (more) |
— | almost 3 years ago |
Comment | Post #282013 |
Also asked at https://matheducators.stackexchange.com/q/20959/77 (more) |
— | almost 3 years ago |
Comment | Post #280910 |
Thanks for the response. I've deleted my comment (which contained a mistake). (more) |
— | about 3 years ago |
Comment | Post #280910 |
Your formula is incorrect. It uses the "equals" symbol when you yourself state that the equality doesn't hold when a=1, b=5. Perhaps you meant to use an "approximately equal to" symbol? (more) |
— | about 3 years ago |
Comment | Post #280741 |
Previously asked at https://matheducators.stackexchange.com/q/19418/77. (more) |
— | about 3 years ago |