Picking 20 different numbers, in the same draw vs. picking 10 different numbers, in 2 different draws.
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Does Pr (probability) of winning jackpot differ between
1. picking 20 different #s, for the same draw
vs.
2. picking 10 different #s, for 2 different draws ?
Intuitively, purchase 1 results in a low Pr(winning jackpot). Why? In 1 ― you picked
In 2 ― you picked
Doubtless,
1 answer
Does Pr (probability) of winning jackpot differ between 1. picking 20 different #s, for the same draw vs. 2. picking 10 different #s, for 2 different draws ?
Yes. Consider the limiting case where there are only 20 possible choices. Playing all 20 numbers guarantees a win. Playing 10 out of 20 choices results in probability of winning of ½. Therefore playing 10 choices each in two different draws results in a probability of winning of ¾.
Note here that "winning" is used only to mean picking the winning number. It does not imply being better off at the end or a positive expected value. In any remotely competent lottery, it would cost more to play every possible number than you get by winning.
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