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#2: Post edited by user avatar trichoplax‭ · 2023-01-31T08:06:30Z (about 1 year ago)
Remove redundant commentary on the question
  • Your request doesn't make much sense. If you only have one X-Y pair to meet, then a constant fits the specs perfectly:
  • &nbsp; &nbsp; f(x) = K
  • If it has to meet two X-Y pairs, then a line does it:
  • &nbsp; &nbsp; f(x) = K<sub>1</sub>x + K<sub>2</sub>
  • A quadratic can hit three points:
  • &nbsp; &nbsp; f(x) = K<sub>1</sub>x<sup>2</sup> + K<sub>2</sub>x + K<sub>3</sub>
  • This is also known as a "second order" polynomial. Each additional order allows the function to hit one more point exactly (within some limits, like they all have to have different X values).
  • If you only have one X-Y pair to meet, then a constant fits the specs perfectly:
  • &nbsp; &nbsp; f(x) = K
  • If it has to meet two X-Y pairs, then a line does it:
  • &nbsp; &nbsp; f(x) = K<sub>1</sub>x + K<sub>2</sub>
  • A quadratic can hit three points:
  • &nbsp; &nbsp; f(x) = K<sub>1</sub>x<sup>2</sup> + K<sub>2</sub>x + K<sub>3</sub>
  • This is also known as a "second order" polynomial. Each additional order allows the function to hit one more point exactly (within some limits, like they all have to have different X values).
#1: Initial revision by user avatar Olin Lathrop‭ · 2023-01-30T21:09:14Z (about 1 year ago)
Your request doesn't make much sense.  If you only have one X-Y pair to meet, then a constant fits the specs perfectly:

&nbsp; &nbsp; f(x) = K

If it has to meet two X-Y pairs, then a line does it:

&nbsp; &nbsp; f(x) = K<sub>1</sub>x + K<sub>2</sub>

A quadratic can hit three points:

&nbsp; &nbsp; f(x) = K<sub>1</sub>x<sup>2</sup> + K<sub>2</sub>x + K<sub>3</sub>

This is also known as a "second order" polynomial.  Each additional order allows the function to hit one more point exactly (within some limits, like they all have to have different X values).