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Comments on Without trial and error, average(average(a,b),c) vs. average(a,average(b,c)).

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Without trial and error, average(average(a,b),c) vs. average(a,average(b,c)). [closed]

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Closed as unclear by Peter Taylor‭ on Nov 27, 2021 at 20:54

This question cannot be answered in its current form, because critical information is missing.

This question was closed; new answers can no longer be added. Users with the reopen privilege may vote to reopen this question if it has been improved or closed incorrectly.

EXCLUDE Trial and Error. If $a = b = c = 0$, then obviously both sides are equal. My child is 14 y.o. We prefer pretty proofs by picture (but beware), AND intuition! Recondite algebra is not required.

But how do I systematically deduce when $\overline{\overline{a, b}, c} = \frac{a}{4}+ \frac{b}{4} + \frac{c}{2}$

  • = AND
  • $\neq$

$\overline{a, \overline{b, c}} = \frac{a}{2} + \frac{b}{4} + \frac{c}{4}$?

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3 comment threads

Post Feedback (4 comments)
I can't even guess at what you're asking. (1 comment)
I do appreciate the irony though (1 comment)
I can't even guess at what you're asking.
Peter Taylor‭ wrote over 2 years ago

I can't even guess at what you're asking.