Comments on Without trial and error, average(average(a,b),c) vs. average(a,average(b,c)).
Post
Without trial and error, average(average(a,b),c) vs. average(a,average(b,c)). [closed]
Closed as unclear by Peter Taylor on Nov 27, 2021 at 20:54
This question cannot be answered in its current form, because critical information is missing.
This question was closed; new answers can no longer be added. Users with the reopen privilege may vote to reopen this question if it has been improved or closed incorrectly.
EXCLUDE Trial and Error. If $a = b = c = 0$, then obviously both sides are equal. My child is 14 y.o. We prefer pretty proofs by picture (but beware), AND intuition! Recondite algebra is not required.
But how do I systematically deduce when $\overline{\overline{a, b}, c} = \frac{a}{4}+ \frac{b}{4} + \frac{c}{2}$
- = AND
- $\neq$
$\overline{a, \overline{b, c}} = \frac{a}{2} + \frac{b}{4} + \frac{c}{4}$?
3 comment threads