Comments on Prove $(\cos^3\theta+\sin^3\theta)^2= \cos^6\theta(1+\tan^3\theta)^2$
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Prove $(\cos^3\theta+\sin^3\theta)^2= \cos^6\theta(1+\tan^3\theta)^2$
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$$(\cos^3\theta+\sin^3\theta)^2= \cos^6 \theta(1+\tan^3\theta)^2$$
How to prove the above sum? I was looking at triple angle formula but, i couldn’t find relation between tan sin cos in triple angle formula.
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$$(a+b)^2 = a^2 \left(1 + \frac ba\right)^2$$
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