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(\cos^{3} θ + \sin^{3} θ)^{2} = \cos^{6} θ (1 + \tan^{3} θ)^{2}

2 answers · posted 3y ago by deleted user · last activity 3y ago by Peter Taylor‭

Question trigonometry

#3: Post edited by (deleted user) · 2021-08-07T05:59:41Z (over 3 years ago)

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~~Prove $(\cos^{3} θ + \sin^{3} θ)^{2} = \cos^{6} (1 + \tan^{3} θ)^{2}$~~

Prove $(\cos^3\theta+\sin^3\theta)^2= \cos^6\theta(1+\tan^3\theta)^2$

#2: Post edited by (deleted user) · 2021-08-07T05:43:14Z (over 3 years ago)
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~~$(\cos^{3} θ + \sin^{3} θ)^{2} = \cos^{6} (1 + \tan^{3} θ)^{2}$~~
How to prove the above sum? I was looking at triple angle formula but, i couldn’t find relation between tan sin cos in triple angle formula.

$$(\cos^3\theta+\sin^3\theta)^2= \cos^6 \theta(1+\tan^3\theta)^2$$
How to prove the above sum? I was looking at triple angle formula but, i couldn’t find relation between tan sin cos in triple angle formula.

#1: Initial revision by (deleted user) · 2021-08-06T13:12:54Z (over 3 years ago)

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Prove $(\cos^3\theta+\sin^3\theta)^2= \cos^6(1+\tan^3\theta)^2$

$$(\cos^3\theta+\sin^3\theta)^2= \cos^6(1+\tan^3\theta)^2$$

How to prove the above sum? I was looking at triple angle formula but, i couldn’t find relation between tan sin cos in triple angle formula.

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