Activity for KamilPrzespolewski
Type | On... | Excerpt | Status | Date |
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Comment | Post #291528 |
Hi, thanks for pointing this out. I have clarified the reference. (more) |
— | 6 months ago |
Edit | Post #291528 |
Post edited: Clarified reference |
— | 6 months ago |
Edit | Post #291528 | Initial revision | — | 6 months ago |
Question | — |
Does "shift of terms" in a Faber–Schauder series expansion of f ∈ C[0,1] produce an element of C[0,1]? Question Let $\{en : n=0, 1, \dots \}$ be a Faber–Schauder basis (See Megginson Theory of linear operations, 4.1.11 Example). Is the following function from $C[0,1] \times \mathbb{R}$ to $C[0,1]$ well-defined: $$ (f, \beta) = (\sum \alphan en, \beta) \mapsto \beta e0 + \sum \alphan e{n+1} ... (more) |
— | 6 months ago |