Activity for Giannisâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Edit | Post #284218 | Initial revision | — | about 5 years ago |
| Answer | — |
A: How would you vaticinate to $-w_k$ from both sides of $w_{k + 1} = \dfrac{w_k - (1 - p)w_{k - 1}}{p}$? Hi there, So, I'll start first with a few notations. Three sentences above, from the green underlined sentence, you will see that it defines as $p=P(F)$ and as $q=1-p=P(F^{c})$ and these to probabilities sum to $1$, i.e. $p+q=1$ and that $0<p<1$ (in order to divide later with something that i... (more) |
— | about 5 years ago |
