Activity for Incnis Mrsi
Type | On... | Excerpt | Status | Date |
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Answer | — |
A: Is this topology basis dependent? First of all, the kernel of any $\phi\in V^\ast$ has codimension at most one; more precisely, $\ker\phi = V \Leftrightarrow \phi = 0$ and $\operatorname{codim}\ker\phi = 1$ if equalities are false. Hence $V^{[\ast]} = V^\ast$. Ī̲ suspect that by $V^{[\ast]}$ you really assume a basis-dependent thing,... (more) |
— | about 3 years ago |