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Activity for MathPhysics‭

Type On... Excerpt Status Date
Question MathJax overbrace and commutative diagrams on Math Codidact are not rendered perfectly
There are some MathJax codes having imperfect appearances after/when being rendered. I mention two of them with some examples (I do not have enough time to check others). Since I cannot upload any image on Codidact networks, as I reported the related bug on Meta earlier, I use some sharing website...
(more)
over 3 years ago
Answer A: Existence of a set of all sets
Let $V$ be a set of all sets. According to the Axiom Schema of Comprehension, we can have the following set: $$U= \\{ x\in V \mid x \not \in x \\}.$$ Now, there are two cases: - $U \in U$, which, according to the definition of the set $U$, implies that $U \not \in U$, which is a contradictio...
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over 3 years ago
Question Existence of a set of all sets
Suppose that we have an axiomatic set theory having the following axiom: The Axiom Schema of Comprehension: Let $\mathbf{P}(x)$ be a property of $x$. For any set $A$, there is a set $B$ such that $x\in B$ if and only if $x\in A$ and $\mathbf{P}(x)$. Can a set of all sets exist within such an ax...
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over 3 years ago
Question Some codes are not rendered after saving a post while they are rendered in the preview.
When I was writing this post, I noticed that the color style html codes rendered well in the preview, but after posting, I saw that they were not rendered. I know that all html codes may not be supported on Codidact; however, I expect that those of them rendered in the preview also can be rendered...
(more)
over 3 years ago
Question What topics can I ask about here?
Mathematics Codidact (MCD) is for people studying mathematics at any level and professionals in related fields. The following is an outline of subjects covered in MCD. It is not necessarily a complete set of independent related fields; it only wants to help users to know the scope of MCD. If yo...
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over 3 years ago
Answer A: Similar triangles with the same area
One can easily prove the following fact: If two triangles are similar, then the ratio of their areas is the square of the ratio of their sides. Now, if two similar triangles have the same area, it follows that the ratio of the corresponding sides must be the square root of $1$, which is $1$. So...
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over 3 years ago