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#2: Post edited
by
LL 3.14
·
2024-03-07T09:47:46Z (9 months ago)
- At the $0$ order of derivatives of Sobolev spaces, we find Besov spaces $\dot{B}^0_{p,q}$, Triebel Lizorkin spaces $\dot{F}^0_{p,q}$ and Lorentz spaces $L^{p,q}$, with in particular if $p≥ 2$
- $$
\begin{align*}\dot{B}^0_{p,1} ⊂ \dot{B}^0_{p,2} ⊂ L^p &= \dot{F}^0_{p,2} \subset \dot{F}^0_{p,p} =\dot{B}^0_{p,p} ⊂ \dot{B}^0_{p,\infty}\\L^{p,1} \subset L^{p,2} ⊂ L^{p} &= L^{p,p} \subset L^{p,\infty}.\end{align*}- $$
- So, the ordering is well understood when remaining either in the $B,F$ setting, either in the Lorentz setting. so my question is **Is there any embedding from one setting into the other one?**
- ----
- The way of building these spaces is different (in one case one cuts in frequency and in the other one cuts in height). However, Sobolev embeddings tells us that we can trade a bit of local regularity for a bit of local integrability. Moreover the function $|x|^{-a}$ is in both $\dot{B}^{0}_{d/a,\infty}$ and $L^{d/a,\infty}$, but not in $L^{d/a}$.
- At the $0$ order of derivatives of Sobolev spaces, we find Besov spaces $\dot{B}^0_{p,q}$, Triebel Lizorkin spaces $\dot{F}^0_{p,q}$ and Lorentz spaces $L^{p,q}$, with in particular if $p≥ 2$
- $$
- \dot{B}^0_{p,1} ⊂ \dot{B}^0_{p,2} ⊂ L^p = \dot{F}^0_{p,2} \subset \dot{F}^0_{p,p} =\dot{B}^0_{p,p} ⊂ \dot{B}^0_{p,\infty}
- $$
- $$
- L^{p,1} \subset L^{p,2} ⊂ L^{p} = L^{p,p} \subset L^{p,\infty}.
- $$
- So, the ordering is well understood when remaining either in the $B,F$ setting, either in the Lorentz setting. so my question is **Is there any embedding from one setting into the other one?**
- ----
- The way of building these spaces is different (in one case one cuts in frequency and in the other one cuts in height). However, Sobolev embeddings tells us that we can trade a bit of local regularity for a bit of local integrability. Moreover the function $|x|^{-a}$ is in both $\dot{B}^{0}_{d/a,\infty}$ and $L^{d/a,\infty}$, but not in $L^{d/a}$.
#1: Initial revision
by
LL 3.14
·
2024-03-07T09:46:41Z (9 months ago)
Besov or Triebel-Lizorkin spaces versus Lorentz spaces
At the $0$ order of derivatives of Sobolev spaces, we find Besov spaces $\dot{B}^0_{p,q}$, Triebel Lizorkin spaces $\dot{F}^0_{p,q}$ and Lorentz spaces $L^{p,q}$, with in particular if $p≥ 2$
$$
\begin{align*}
\dot{B}^0_{p,1} ⊂ \dot{B}^0_{p,2} ⊂ L^p &= \dot{F}^0_{p,2} \subset \dot{F}^0_{p,p} =\dot{B}^0_{p,p} ⊂ \dot{B}^0_{p,\infty}
\\
L^{p,1} \subset L^{p,2} ⊂ L^{p} &= L^{p,p} \subset L^{p,\infty}.
\end{align*}
$$
So, the ordering is well understood when remaining either in the $B,F$ setting, either in the Lorentz setting. so my question is **Is there any embedding from one setting into the other one?**
----
The way of building these spaces is different (in one case one cuts in frequency and in the other one cuts in height). However, Sobolev embeddings tells us that we can trade a bit of local regularity for a bit of local integrability. Moreover the function $|x|^{-a}$ is in both $\dot{B}^{0}_{d/a,\infty}$ and $L^{d/a,\infty}$, but not in $L^{d/a}$.