Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Post History

71%
+3 −0
Q&A Is there a $(n_3)$ configuration which is not self-dual?

1 answer  ·  posted 12mo ago by WheatWizard‭  ·  last activity 12mo ago by Peter Taylor‭

Question combinatorics
#3: Post edited by user avatar WheatWizard‭ · 2024-01-04T15:22:35Z (12 months ago)
  • Coxeter points out that for a self-dual configuration $(m_c,n_d)$ it must be that $m=n$ and $c=d$, so we may abbreviate it $m_c$.
  • However I'm interested in the other direction of this implication, i.e. is there a configuration $(m_c,m_c)$ which is not self-dual? For $c=2$ there is none. All polygons are combinatorially self-dual.
  • It's also clear that if the automorphism group of the configuration is flag-transitive, then it is of the form $_n\{p\}_n$ and must be self dual. (All polygons fall into this category.)
  • However this still leaves a lot of open cases. In particular I am interested in 3-configurations.
  • Is there a $(n_3)$ configuration which is not self-dual?
  • ### References
  • * Coxeter, (1950) *Self-dual configurations and regular graphs*.
  • Coxeter points out that for a self-dual configuration $(m_c,n_d)$ it must be that $m=n$ and $c=d$, so we may abbreviate it $(m_c)$.
  • However I'm interested in the other direction of this implication, i.e. is there a configuration $(m_c,m_c)$ which is not self-dual? For $c=2$ there is none. All polygons are combinatorially self-dual.
  • It's also clear that if the automorphism group of the configuration is flag-transitive, then it is of the form $_n\{p\}_n$ and must be self dual. (All polygons fall into this category.)
  • However this still leaves a lot of open cases. In particular I am interested in 3-configurations.
  • Is there a $(n_3)$ configuration which is not self-dual?
  • ### References
  • * Coxeter, (1950) *Self-dual configurations and regular graphs*.
#2: Post edited by user avatar WheatWizard‭ · 2024-01-04T04:26:42Z (12 months ago)
A little about the automorphism group.
  • Coxeter points out that for a self-dual configuration $(m_c,n_d)$ it must be that $m=n$ and $c=d$, so we may abbreviate it $m_c$.
  • However I'm interested in the other direction of this implication, i.e. is there a configuration $(m_c,m_c)$ which is not self-dual? For $c=2$ there is none. All polygons are combinatorially self-dual.
  • However for 3-configurations it is not as apparent.
  • Is there a $(n_3)$ configuration which is not self-dual?
  • ### References
  • * Coxeter, (1950) *Self-dual configurations and regular graphs*.
  • Coxeter points out that for a self-dual configuration $(m_c,n_d)$ it must be that $m=n$ and $c=d$, so we may abbreviate it $m_c$.
  • However I'm interested in the other direction of this implication, i.e. is there a configuration $(m_c,m_c)$ which is not self-dual? For $c=2$ there is none. All polygons are combinatorially self-dual.
  • It's also clear that if the automorphism group of the configuration is flag-transitive, then it is of the form $_n\{p\}_n$ and must be self dual. (All polygons fall into this category.)
  • However this still leaves a lot of open cases. In particular I am interested in 3-configurations.
  • Is there a $(n_3)$ configuration which is not self-dual?
  • ### References
  • * Coxeter, (1950) *Self-dual configurations and regular graphs*.
#1: Initial revision by user avatar WheatWizard‭ · 2024-01-04T03:47:14Z (12 months ago)
Is there a $(n_3)$ configuration which is not self-dual?
Coxeter points out that for a self-dual configuration $(m_c,n_d)$ it must be that $m=n$ and $c=d$, so we may abbreviate it $m_c$.

However I'm interested in the other direction of this implication, i.e. is there a configuration $(m_c,m_c)$ which is not self-dual? For $c=2$ there is none. All polygons are combinatorially self-dual.

However for 3-configurations it is not as apparent.

Is there a $(n_3)$ configuration which is not self-dual?

### References

* Coxeter, (1950) *Self-dual configurations and regular graphs*.