Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Post History

#2: Post edited by user avatar Hudjefa‭ · 2023-09-16T02:39:56Z (about 1 year ago)
  • My two cents ... for what they're worth.
  • Imagine someone places 4 identical boxes in front of you. All of the boxes contain 4 identical cups of coffee each (4 × 4 = 16 cups of coffee that are indistinguishable from each other). In 3 of the boxes all the cups are laced with poison (injures, doesn't kill). In one box, only 3 cups contain poision.
  • You are to select a box and then select a cup of coffe which you must drink. Remember all the boxes look identical and the cups of coffee too are identical i.e. you'll have to guess.
  • **The probability that you have a chance of avoiding injury** = 1/4 = 25% (you choose the box that contains 1 cup of coffee that isn't poisoned; call this box J)
  • Once you've selected this particular box (J), you'll have to pick the coffee that isn't poisoned. **The probability of avoiding injury** = 1/4 = 25%.
  • My two cents ... for what they're worth.
  • Imagine someone places 4 identical boxes (A, B, C, D) in front of you. All of the boxes contain 4 identical cups of coffee each (4 × 4 = 16 cups of coffee that are indistinguishable from each other). In 3 of the boxes all the cups are laced with poison (injures, doesn't kill). In one box, only 3 cups contain poison.
  • You are to select a box and then select a cup of coffee which you must drink. Remember all the boxes look identical and the cups of coffee too are identical i.e. you'll have to guess.
  • **The probability that you have a chance of avoiding injury** = 1/4 = 25% (you choose the box that contains 1 cup of coffee that isn't poisoned; call this box C)
  • Once you've selected this particular box C, you'll have to pick the coffee that isn't poisoned. **The probability of avoiding injury** = 1/4 = 25%.
#1: Initial revision by user avatar Hudjefa‭ · 2023-09-15T16:52:30Z (about 1 year ago)
My two cents ... for what they're worth.

Imagine someone places 4 identical boxes in front of you. All of the boxes contain 4 identical cups of coffee each (4 × 4 = 16 cups of coffee that are indistinguishable from each other). In 3 of the boxes all the cups are laced with poison (injures, doesn't kill). In one box, only 3 cups contain poision. 

You are to select a box and then select a cup of coffe which you must drink. Remember all the boxes look identical and the cups of coffee too are identical i.e. you'll have to guess.

**The probability that you have a chance of avoiding injury** = 1/4 = 25% (you choose the box that contains 1 cup of coffee that isn't poisoned; call this box J)

Once you've selected this particular box (J), you'll have to pick the coffee that isn't poisoned. **The probability of avoiding injury** = 1/4 = 25%.