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#2: Post edited by user avatar Chgg Clou‭ · 2022-10-09T00:25:15Z (about 2 years ago)
  • On one hand, I know that algebraically, $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$.
  • On the other hand, they differ in practice, not least because $\color{red}{1/3}$ contains 3 as the repetend. For example, if I need a physical scrap of material to have a 3:1 ratio but have a length of 3 m, then I can fulfill this requirement by making the width 1 m.
  • But presuppose a length of 1 m. Then a 3:1 ratio is impossible to accomplish, because a 3:1 ratio would require a width of $\color{red}{1/3=0.\overline{3}}$. But it's impossible to measure and cut anything physical at a repeating decimal!
  • Doesn't this physical impossibility due to the reptend belie, or undermine, the theoretical "equality" that $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$? How can this physical impossibility due to the repetend be reconciled with equality?
  • ![](https://www.mathsisfun.com/numbers/images/ratio-3-1b.svg)
  • On one hand, I know that algebraically, $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$.
  • On the other hand, they differ in practice, not least because $\color{red}{1/3}$ contains 3 as the repetend. For example, if a scrap of physical material must have a 3:1 ratio and a length of 3 m, then I shall make the width 1 m.
  • But presuppose a length of 1 m. Then a 3:1 ratio is impossible to accomplish, because it would require a width of $\color{red}{1/3=0.\overline{3}}$. But it's impossible to measure and cut anything physical at a repetend!
  • Doesn't this physical impossibility due to the reptend belie, or undermine, the theoretical "equality" that $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$? How can this physical impossibility due to the repetend be reconciled with equality?
  • ![](https://www.mathsisfun.com/numbers/images/ratio-3-1b.svg)
#1: Initial revision by user avatar Chgg Clou‭ · 2022-10-09T00:23:58Z (about 2 years ago)
How can 3/1 ≡ 1/(1/3), when left side features merely integers, but right side features a repetend? 
On one hand, I know that algebraically, $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$.

On the other hand, they differ in practice, not least because $\color{red}{1/3}$ contains 3 as the repetend. For example, if I need a physical scrap of material to have a 3:1 ratio but have a length of 3 m, then I can fulfill this requirement by making the width 1 m.

But presuppose a length of 1 m. Then a 3:1 ratio is impossible to accomplish, because a 3:1 ratio would require a width of $\color{red}{1/3=0.\overline{3}}$. But it's impossible to measure and cut anything physical at a repeating decimal! 

Doesn't this physical impossibility due to the reptend belie, or undermine, the theoretical "equality" that  $\dfrac{3}1 ≡ \dfrac{1}{\color{red}{1/3}}$? How can this physical impossibility due to the repetend be reconciled with equality?




![](https://www.mathsisfun.com/numbers/images/ratio-3-1b.svg)