Post History
#3: Post edited
by
whybecause
·
2021-12-31T02:19:56Z (almost 3 years ago)
A possibly helpful further note beyond the answers given elsewhere here: Do you intuitively understand why $ab=c$ is equivalent to $a=b/c$ for all $ce 0$? If so, and if you intuitively understand the commutativity of multiplication, then these two intuitions put together give you everything that you need.- The intuition for the commutativity of multiplication is really easy to come up with so I won't argue that case.
But the equivalence of $ab=c$ and $a=b/c$ is basically just down to *what we mean by division*.
- A possibly helpful further note beyond the answers given elsewhere here: Do you intuitively understand why $ab=c$ is equivalent to $a=c/b$ for all $b
- e 0$? If so, and if you intuitively understand the commutativity of multiplication, then these two intuitions put together give you everything that you need.
- The intuition for the commutativity of multiplication is really easy to come up with so I won't argue that case.
- But the equivalence of $ab=c$ and $a=c/b$ is basically just down to *what we mean by division*.
#2: Post edited
by
whybecause
·
2021-12-30T22:24:21Z (almost 3 years ago)
A possibly helpful further note beyond the answers given below: Do you intuitively understand why $ab=c$ is equivalent to $a=b/c$ for all $ce 0$? If so, and if you intuitively understand the commutativity of multiplication, then these two intuitions put together give you everything that you need.- The intuition for the commutativity of multiplication is really easy to come up with so I won't argue that case.
- But the equivalence of $ab=c$ and $a=b/c$ is basically just down to *what we mean by division*.
- A possibly helpful further note beyond the answers given elsewhere here: Do you intuitively understand why $ab=c$ is equivalent to $a=b/c$ for all $c
- e 0$? If so, and if you intuitively understand the commutativity of multiplication, then these two intuitions put together give you everything that you need.
- The intuition for the commutativity of multiplication is really easy to come up with so I won't argue that case.
- But the equivalence of $ab=c$ and $a=b/c$ is basically just down to *what we mean by division*.
#1: Initial revision
by
whybecause
·
2021-12-30T22:24:06Z (almost 3 years ago)
A possibly helpful further note beyond the answers given below: Do you intuitively understand why $ab=c$ is equivalent to $a=b/c$ for all $c\ne 0$? If so, and if you intuitively understand the commutativity of multiplication, then these two intuitions put together give you everything that you need. The intuition for the commutativity of multiplication is really easy to come up with so I won't argue that case. But the equivalence of $ab=c$ and $a=b/c$ is basically just down to *what we mean by division*.