Post History
#4: Post edited
by
General Sebast1an
·
2021-10-30T05:23:34Z (about 3 years ago)
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
- Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. What does "no addition" mean here? Basically, you can't use the addition operator in the equation. In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator. No $\sum$ either.
- So what else? "I tried many times to make such equation." Here's an example I did with $2 + 3 = 5$:
- $$2 + 3 = 5$$
- $$2 \times 3 = 6 \ne 5$$
- $$6 - (3 - 2) = 6 - 1 = 5$$
- So I thought $(a \times b) - (b - a)$ was plausible, but then I tried $3 + 6 = 9$:
- $$3 + 6 = 9$$
- $$3 \times 6 = 18 \ne 9$$
- $$18 - (6 - 3) = 18 - 3 = 15 \ne 9$$
I haven't tried division yet because it can result to decimals.- If it is even possible, can you get 2 values to result to their sum without any form of addition?
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
- Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. What does "no addition" mean here? Basically, you can't use the addition operator in the equation. In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator. No $\sum$ either.
- So what else? "I tried many times to make such equation." Here's an example I did with $2 + 3 = 5$:
- $$2 + 3 = 5$$
- $$2 \times 3 = 6 \ne 5$$
- $$6 - (3 - 2) = 6 - 1 = 5$$
- So I thought $(a \times b) - (b - a)$ was plausible, but then I tried $3 + 6 = 9$:
- $$3 + 6 = 9$$
- $$3 \times 6 = 18 \ne 9$$
- $$18 - (6 - 3) = 18 - 3 = 15 \ne 9$$
- I haven't tried division yet because it can result to decimals, and we all know how fuzzy they are.
- If it is even possible, can you get 2 values to result to their sum without any form of addition?
#3: Post edited
by
General Sebast1an
·
2021-10-30T05:19:59Z (about 3 years ago)
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
- Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. What does "no addition" mean here? Basically, you can't use the addition operator in the equation. In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator. No $\sum$ either.
- So what else? "I tried many times to make such equation." Here's an example I did with $2 + 3 = 5$:
- $$2 + 3 = 5$$
- $$2 \times 3 = 6 \ne 5$$
- $$6 - (3 - 2) = 6 - 1 = 5$$
- So I thought $(a \times b) - (b - a)$ was plausible, but then I tried $3 + 6 = 9$:
- $$3 + 6 = 9$$
$$3 * 6 = 18e 9$$- $$18 - (6 - 3) = 18 - 3 = 15 \ne 9$$
- I haven't tried division yet because it can result to decimals.
- If it is even possible, can you get 2 values to result to their sum without any form of addition?
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
- Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. What does "no addition" mean here? Basically, you can't use the addition operator in the equation. In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator. No $\sum$ either.
- So what else? "I tried many times to make such equation." Here's an example I did with $2 + 3 = 5$:
- $$2 + 3 = 5$$
- $$2 \times 3 = 6 \ne 5$$
- $$6 - (3 - 2) = 6 - 1 = 5$$
- So I thought $(a \times b) - (b - a)$ was plausible, but then I tried $3 + 6 = 9$:
- $$3 + 6 = 9$$
- $$3 \times 6 = 18
- e 9$$
- $$18 - (6 - 3) = 18 - 3 = 15 \ne 9$$
- I haven't tried division yet because it can result to decimals.
- If it is even possible, can you get 2 values to result to their sum without any form of addition?
#2: Post edited
by
General Sebast1an
·
2021-10-30T05:18:10Z (about 3 years ago)
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. No subtracting the additive inverse of $b$ from $a$, because that's pretty much just addition. I tried searching ways, but I encountered programming answers instead. Not what I want.- If it is even possible, can you get 2 values to result to their sum without any form of addition?
- Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation.
- Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. What does "no addition" mean here? Basically, you can't use the addition operator in the equation. In fact, subtracting the additive inverse of $b$ to $a$ still counts as using the addition operator. No $\sum$ either.
- So what else? "I tried many times to make such equation." Here's an example I did with $2 + 3 = 5$:
- $$2 + 3 = 5$$
- $$2 \times 3 = 6 \ne 5$$
- $$6 - (3 - 2) = 6 - 1 = 5$$
- So I thought $(a \times b) - (b - a)$ was plausible, but then I tried $3 + 6 = 9$:
- $$3 + 6 = 9$$
- $$3 * 6 = 18 \ne 9$$
- $$18 - (6 - 3) = 18 - 3 = 15 \ne 9$$
- I haven't tried division yet because it can result to decimals.
- If it is even possible, can you get 2 values to result to their sum without any form of addition?
#1: Initial revision
by
General Sebast1an
·
2021-10-29T18:24:39Z (about 3 years ago)
Can we add without using addition?
Is there a formula that applies $a + b = c$ without addition. I tried many times to make such equation. Here's what I have in mind, we get 2 values, call them $a$ and $b$. The objective is to get the sum, without using addition at all. No subtracting the additive inverse of $b$ from $a$, because that's pretty much just addition. I tried searching ways, but I encountered programming answers instead. Not what I want. If it is even possible, can you get 2 values to result to their sum without any form of addition?