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#1: Initial revision by (deleted user) · 2021-08-31T15:08:18Z (over 3 years ago)
Getting backward of partial differentiation's chain rule
We know that Chain rule of partial derivatives is something just like this ($z$ is function of $x$ and $y$ variable and, $x$ and $y$ is function of $t$) :

$$\frac{dz}{dt}=\frac{\partial z}{\partial x} \frac{\partial x}{\partial t}+\frac{\partial z}{\partial y} \frac{\partial y}{\partial t}$$

Then, I was thinking to getting backward from the equation.

$$\frac{\partial z}{\partial x} \frac{\partial x}{\partial t}+\frac{\partial z}{\partial y} \frac{\partial y}{\partial t} =\frac{\partial z}{\partial t}+\frac{\partial z}{\partial t}=2\frac{\partial z}{\partial t}$$

Can't we write that $\frac{\partial z}{\partial t}=\frac{dz}{dt}$? If not, than what's the difference between them? If yes, than why I couldn't prove backward?

From my study of Calculus, I read that $\frac{d}{dt}$ is used for total differentiation. And, $\frac{\partial }{\partial t}$ is some differentiation under $\frac{d}{dt}$. But, I am not sure if that's correct.