Post History
#5: Post edited
by
DNB
·
2021-08-10T00:28:21Z (over 3 years ago)
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers as much as possible. Please explain using solely the circle pictograms. Undeniably, I'm NOT asking about how to divide numbers.
- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. The website postulates P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%. What fraction of patients who tested positive are diseased?
- >3/7 or 43%, quickly obtainable as follows: In the screened population, there's 1 sick patient for 4 healthy patients. Sick patients are 3 times more likely to turn the tongue depressor black than healthy patients. $(1:4)⋅(3:1)=(3:4)$ or 3 sick patients to 4 healthy patients among those that turn the tongue depressor black, corresponding to a probability of 3/7=43% that the patient is sick.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
$\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers as much as possible. Please explain using solely the circle pictograms. Undeniably, I'm NOT asking about how to divide numbers.
- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. The website postulates P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%. What fraction of patients who tested positive are diseased?
- >3/7 or 43%, quickly obtainable as follows: In the screened population, there's 1 sick patient for 4 healthy patients. Sick patients are 3 times more likely to turn the tongue depressor black than healthy patients. $(1:4)⋅(3:1)=(3:4)$ or 3 sick patients to 4 healthy patients among those that turn the tongue depressor black, corresponding to a probability of 3/7=43% that the patient is sick.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{\color{red}P(+|D)} {\color{deepskyblue}{P(+|D^C)}} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$
#4: Post edited
by
DNB
·
2021-08-10T00:16:13Z (over 3 years ago)
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers as much as possible. Please explain using solely the circle pictograms. Undeniably, I'm NOT asking about how to divide numbers.
I don't understand 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (representing P(+))?- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. The website postulates P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%. What fraction of patients who tested positive are diseased?
- >3/7 or 43%, quickly obtainable as follows: In the screened population, there's 1 sick patient for 4 healthy patients. Sick patients are 3 times more likely to turn the tongue depressor black than healthy patients. $(1:4)⋅(3:1)=(3:4)$ or 3 sick patients to 4 healthy patients among those that turn the tongue depressor black, corresponding to a probability of 3/7=43% that the patient is sick.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers as much as possible. Please explain using solely the circle pictograms. Undeniably, I'm NOT asking about how to divide numbers.
- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. The website postulates P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%. What fraction of patients who tested positive are diseased?
- >3/7 or 43%, quickly obtainable as follows: In the screened population, there's 1 sick patient for 4 healthy patients. Sick patients are 3 times more likely to turn the tongue depressor black than healthy patients. $(1:4)⋅(3:1)=(3:4)$ or 3 sick patients to 4 healthy patients among those that turn the tongue depressor black, corresponding to a probability of 3/7=43% that the patient is sick.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
#3: Post edited
by
DNB
·
2021-08-10T00:13:09Z (over 3 years ago)
Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers.- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (representing P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%.- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers as much as possible. Please explain using solely the circle pictograms. Undeniably, I'm NOT asking about how to divide numbers.
- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (representing P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. The website postulates P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%. What fraction of patients who tested positive are diseased?
- >3/7 or 43%, quickly obtainable as follows: In the screened population, there's 1 sick patient for 4 healthy patients. Sick patients are 3 times more likely to turn the tongue depressor black than healthy patients. $(1:4)⋅(3:1)=(3:4)$ or 3 sick patients to 4 healthy patients among those that turn the tongue depressor black, corresponding to a probability of 3/7=43% that the patient is sick.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
#2: Post edited
by
DNB
·
2021-08-10T00:10:40Z (over 3 years ago)
Here I'm asking solely about the circle pictograms below, not the integers. I don't understand the meaning of- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
$\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+}$
- Here I'm asking solely about the circle pictograms. Please eschew referring to, or using, numbers.
- I don't understand 
- 1. How do I "visually" divide Circle 1 (representing $P(+ \cap D)$) by Circle 2 (P(+)) into Circle 3 (representing P(+))?
- 2. I see that the bottom gray areas in Circles 1 and 3 disappear, but how does this pictorialize division?
- I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%.
- >Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
- >
- "the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
- $\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+)}$.
#1: Initial revision
by
DNB
·
2021-08-10T00:04:16Z (over 3 years ago)
How to visualize division in the Odds form of Bayes's Theorem?
Here I'm asking solely about the circle pictograms below, not the integers. I don't understand the meaning of
I first precis the [problem statement and percentages](https://arbital.com/p/bayes_rule/?l=693). Abbreviate Disease to D, positive test result to +. 1. P(D) = 20%, P(+|D) = 90%, P(+|D^C) = 30%.
>Using red for sick, blue for healthy, grey for a mix of sick and healthy patients, and + signs for positive test results, the proof above can be visualized as follows:
>
"the proof above" refers to the Odds form of Bayes's Rule. For clarity, I replace the website's $H_j$ with $D$, $H_k$ with $D^C$ and $e_0$ with $+$.
$\dfrac{P(D)}{P(D^C)} \times \dfrac{P(+|D)}{P(+|D^C)} = \dfrac{P(+ \cap D)}{P(+ \cap D^C)} = \dfrac{P(+ \cap D)/P(+)}{P(+ \cap D^C)/P(+)} = \dfrac{P(D|+)}{P(D^C|+}$