#1: Initial revision
by
(deleted user)
·
2021-08-07T14:57:37Z (over 3 years ago)
Forget about specific value, and think of a square. Consider
$$f(x)=s$$ and, $$x\in[0,s]$$.
$$A_\square=\int_0^s s\mathrm dx$$
$$=[sx]_0^s$$
$$=s^2$$
That's formula for area of square.
