Please see the embolded phrase below. How can you explain to a 9 year old why you
1. must divide by $c$?
2. can't subtract by $c$?
>### 1.4.2 Adjusting for overcounting
>In many counting problems, it is not easy to directly count each possibility once
and only once. If, however, we are able to count each possibility exactly c times for some c, then we can adjust **by dividing by $c$**. For example, if we have exactly
double-counted each possibility, we can divide by 2 to get the correct count. We call
this _adjusting for overcounting_.
Blitzstein. *Introduction to Probability* (2019 2 ed). pp. 14-15.
DNB
·
2021-07-09T04:33:28Z (over 3 years ago)