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Comments on Missing a solution: Are A and B always equal if A-B=0

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Missing a solution: Are A and B always equal if A-B=0

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I just came across this problem on an online learning app:

4x(5−x)−12(5−x)+100=100

I tried to solve it by subtracting 100 from each side then inferring if something minus something else equals zero then those two things must be equal.

4x(5−x)=12(5−x)

Divide both sides by (5-x) and x must be 3.

But brilliant had a different way of solving it that revealed there are two possible values for x.

Where did I make a mistake in my approach to solving the problem?

Is it incorrect to assume that if a minus b equals 0 then a must equal b?

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Dividing by 5-x is valid only if x is not 5. But x=5 is another solution to the original equation.

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2 comment threads

Rule against adding uncertain denominators? (5 comments)
So if 4ab=12b, and you want to know what a is, is it a bad idea to divide both sides by b? Is this e... (2 comments)
So if 4ab=12b, and you want to know what a is, is it a bad idea to divide both sides by b? Is this e...
re89j‭ wrote almost 3 years ago

So if 4ab=12b, and you want to know what a is, is it a bad idea to divide both sides by b? Is this example fundamentally different from dividing both sides by (5-x)? If so, why?

whybecause‭ wrote almost 3 years ago

If b=0 then you may get invalid solutions, yes.

So you should divide this solution method into two cases. Case 1 is that x=5. In that case you cannot divide by x-5, but it doesn't matter, because you already know the solution. Case 2 is that x is not 5. Then you can divide by x and then the rest of your solution is valid.