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Comments on Stone–Čech compactification and ultrafilters

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Stone–Čech compactification and ultrafilters

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Munkres defines the Stone–Čech compactification $\beta X$ of a topological space $X$ as based on the embedding of completely regular spaces into the cube $[0,1]^{\mathcal{CB}(X)}$ where I use $\mathcal{CB}(X)$ to denote the space of bounded continuous functions on $X$. Specifically, any point $h$ in this cube is defined as an assignment of values $f(h)$ for each bounded continuous function $f: X → \mathbb{R}$; and then $\beta X$ is the closure of $X$ in the aforesaid cube.[1]

(More explicitly, we'd write the cube $\mathfrak{C}$ as)

\[\beta X \subseteq \mathfrak{C} := \prod_{f\in\mathcal{CB}(X)} [\text{glb}(f),\text{lub}(f)]\]

(and thus any point $x \in X$ would embed to the point $\{f(x)\}_{f\in\mathcal{CB}(X)}$ in $\mathfrak{C}$.)

This seems like a fairly straightforward definition based on continuous functions. I read in Wikipedia, though, that there is a nontrivially different characterization of the Stone–Čech compactification based on ultrafilters![2]

Is this correct? If so, approximately why is it correct?



  1. For vague intuition, I think we could say that $\beta X$ is almost like a "dual space of the dual space" of $X$. ↩︎

  2. E.g. in Wikipedia's article on the Wallman compactification, which despite being defined based on ultrafilters and not based on bounded continuous functions, is apparently "essentially the same as the Stone–Čech compactification." So I'm wondering why it is that the Wallman and Stone–Čech compactifications would coincide (if indeed they do) on normal spaces. ↩︎

History

1 comment thread

Typing `\text{glb}` rather than `\operatorname{glb}` results in lack of proper spacing in things like... (3 comments)
Typing `\text{glb}` rather than `\operatorname{glb}` results in lack of proper spacing in things like...
Michael Hardy‭ wrote 3 months ago · edited 3 months ago

Typing \text{glb} rather than \operatorname{glb} results in lack of proper spacing in things like $3\text{glb}S$ rather than $3\operatorname{glb}S$ (the latter coded as 3\operatorname{glb}S). In a long document, you needn't type all of \operatorname every time since you can define a short command before \begin{document}. It's not just extra horizontal spacing; rather, the spacing depends on the context.

clemens‭ wrote 3 months ago

Thanks.

By the way can you elaborate on the issue with \Pi and \mathcal? Is it simply that the \mathcal{CB} is not in the right size, shape, etc. when in the subscript of \Pi instead of \prod?

Michael Hardy‭ wrote 3 months ago

\prod is designed to be used in the way you used it in this question. In "inline" (as opposed to "displayed") contexts, the subscript on \prod is below and to the right of the symbol, unless that is manually overridden, as by the use of \displaystyle. But in a "displayed" context, it is directly below the symbol, and superscripts similarly directly above. \Pi, on the other hand is merely a capital Greek letter, not something intended to be used as a symbol in mathematical notation. They look different from each other: $\Pi$ versus $\prod$ or: $$ \begin{align} & \Pi \ & \prod \ & \Pi_{i=1}^n \ & \prod_{i=1}^n \end{align} $$ The same applies to \Sigma versus \sum.