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Comments on Can we add additional structure to the umbral ring?

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Can we add additional structure to the umbral ring?

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As I understand it, umbral calculus by default only postulates the effect of evaluation operator on umbral expressions. This means, we are free to add more axioms and relations between umbral elements as long as it does not break the evaluation properties.

Now consider the expressions

$$\frac{1}{2} \left(e^{2 i \pi B_- x}+e^{2 i \pi B_+ x}\right)$$ and $$x \ln \left(\frac{B_+-x}{B_-+x}\right)$$

where $B_-$ is Bernoulli umbra (an umbra with moments equal to Bernoulli numbers) and $B_+=B_-+1$.

They both have the evalutaion (scalar part) equal to

$$\pi x \cot (\pi x)=1-\frac{\pi ^2 x^2}{3}-\frac{\pi ^4 x^4}{45}-\frac{2 \pi ^6 x^6}{945}-\frac{\pi ^8 x^8}{4725}-\frac{2 \pi ^{10} x^{10}}{93555}-\dots$$

The question is, can we somehow link them, adding more structure to the umbral ring?

$$\frac{1}{2} \left(e^{2 i \pi B_- x}+e^{2 i \pi B_+ x}\right)\stackrel{?}{=}x \ln \left(\frac{B_+-x}{B_-+x}\right)$$

It seems, this cannot be the equality everywhere. For instance, the left-hand part has zeroes at $x=1/2+kx$, $k\in\mathbb{Z}$, while the right-hand part cannot have there zeroes as it would mean that logarithm of something other than $1$ is zero.

But we can speculate that the equality can hold on $x\in(0,1)$ (at $x=0$ and $x=1$ the right-hand side is undefined because $\ln B_-$ has the scalar part diverging). Will this rule break something or add a rich structure to the ring? Maybe the equality can be modified to make it more universal?

Similar question on Stackexchange.

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1 comment thread

Levi–Civita field? (6 comments)
Levi–Civita field?
clemens‭ wrote 4 months ago

I know next to nothing about umbras, but I do know about the Levi–Civita field, and it appears from Wikipedia that the Bernoulli umbra can be embedded in this field.

Perhaps you've found this solution unsatisfactory, though.

Anixx‭ wrote 4 months ago

That embedding breaks with non-natural powers of Bernoulli umbra and the question is whether we can just postulate some simple relations so to enrich the ring's structure. From the proposed equation, for instance, we will get something like $e^{e^{2 i \pi B_-}}=\frac{B_-}{B_+}$ at $x=1$ if we get rid of singularity...

clemens‭ wrote 4 months ago

With non-natural powers—so also with the inverse Bernoulli umbra?

Anixx‭ wrote 4 months ago

Inverse of Bernoulli umbra is not possible in any representation because we cannot divide by it (its scalar part goes to infinity). Generally, we can divide by $B_+=B+1$ but yeah, not in that representation from the article.

clemens‭ wrote 4 months ago

@Anixx: how is it that $B_+$ is an element of the Levi–Civita field without a multiplicative inverse? Am I misunderstanding something?

Anixx‭ wrote 4 months ago · edited 4 months ago

In that model you can find an inverse of that element, but its scalar part will be zero. Real $1/B_+$ has scalar part $\frac{\pi^2}6$. Scalar parts of powers of Bernoulli umbra are generalized via Zeta function: $\operatorname{eval}B_+^x=-x \zeta(1-x)$.