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Comments on Is there a stable/consistent extension of wheel theory to alephs?

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Is there a stable/consistent extension of wheel theory to alephs?

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In wheel theory (MathSE) (see also Wikipedia here and nLab here), $0/0$ is more tractable than usual. There is a unary version of division, $/a$, which is involutive: $//a = a$, and $0/0$ is used as an absorbing element generally. So the theory goes on to allow for working with division by zero to a greater extent than usual.

Now for transfinite cardinals $\aleph_{\alpha}$, division is pretty much not defined. Even self-subtraction is indeterminate in that e.g. $\aleph_0 - \aleph_0$ might cover a situation in which a set of length $\omega$ was subtracted from, say, $\omega + \omega$, leaving countably many elements behind, so that the result of the cardinal subtraction is again $\aleph_0$. Or one might reduce a countable set so as to leave behind 1000 elements, etc. More generally, as $\aleph_0 + n = \aleph_0$, it is possible to have self-subtraction of an aleph leave any n behind, etc.

Similarly, then, and akin also to self-division of zero, $\frac{\aleph_0}{\aleph_0} = X$ can take any value in $[1, \aleph_0]$. (But dividing an aleph by itself and getting 0 is not granted.)

So, would it be possible to expand upon wheel theory to introduce $\aleph_0/\aleph_0$ as a sort of "top element" antipodal to $0/0$ as a bottom element? And then to have $/\aleph_0$, etc. as "cardinal infinitesimals"? (I'm trying to see if we can use infinite cardinals instead of infinite surreals or infinite hypernumbers in the Robinsonian sense, as the base for infinitesimals. Having looked over Jech's book on the axiom of choice, I was also minded to consider non-aleph infinite cardinals $A$ such that $1/A$ is more tractable, but getting to use the alephs for this purpose is my dream...)

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(Update: this answer is not complete; I made a misstep, as you can see in footnote 2. Sorry!)

I shall use a slightly different formalization of wheel theory I read from Sobociński's excellent Graphical Linear Algebra1, where the numbers on the wheel are considered as linear relations between input and output.

Thus, for example, ordinary numbers $n$ are considered as relations ${(x,y): y=nx}$ where the input is $n$ times the output. The inverses of such numbers, $\frac1n$ are considered as relations ${(x,y): x=ny}$ where the output is $n$ times the input.

The only difference between this theory and ordinary wheel theory is that there are two different instances of $\frac00$: one is the trivial relation $\{(x,y): 0x=0y\}$ that allows any input and output (Sobociński calls this $\bot$) and the other is the maximally restrictive relation $\{(x,y): x=0∧y=0\}$ that constrains both input and output to be 0 (Sobociński calls this $\top$).

It is not difficult to extend this to any abelian group. The only snag is that cardinals, as observed in the OP, constitute an abelian monoid and not an abelian group, so we get addition, multiplication, and division but not subtraction.2

However, as we still have subtraction of finite integers, the situation is not unlike that which we already have with wheels and $\frac00$. More precisely, adjoining alephs to Sobociński's system gives us a proper class of new operations $\aleph_\alpha$ each of which are equal to their antipodes and dominate any operators less than or equal to themselves (i.e. $\aleph_\alpha + x = \aleph_\alpha$ whenever $x ≤ \aleph_\alpha$).

But this answer is incomplete, as it is not fully clear how equational rules that allow addition would fit elegantly in this system (e.g. what is $\frac{\aleph_0}{\aleph_0} + \frac00$?).


1(See chapter 26 of his online book, "Keep calm and divide by zero".)

2 The usual way to make an abelian monoid into an abelian group is to form its [Grothendieck group](https://en.wikipedia.org/wiki/Grothendieck group), whose elements are differences $a - b$ where $a - a$ is set to 0 for all $a$. But this does not work properly, because e.g. $1 = (\aleph_0 - \aleph_0) + 1 = \aleph_0 + (-\aleph_0 + 1) = \aleph_0 + (-\aleph_0) = 0$.

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Works for me (3 comments)
Works for me
Ripheus24‭ wrote 7 months ago

Good resources to look into :D

clemens‭ wrote 7 months ago · edited 7 months ago

Hello and welcome to Codidact! I would advise you to remove the "Works for me" endorsement, as in fact I realize that the Grothendieck group approach does not work properly. (Since adding $\aleph_n$ has to be invertible, everything ends up equalling everything else.)

Sobociński's approach can be extended to ordinals (using noncommutative group theory this time, so some of the nice category-theoretic properties he has fail). I shall have to look into r~~'s answer for a way that works.

Ripheus24‭ wrote 7 months ago

clemens‭e OK. I'm mostly in the dark about this beyond what I knew for the basis of my question, and some obsession with proving Euler right about the usefulness of 0/0 :p