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Comments on What is the reason this example of an everywhere surjective function have or does not have an undefined mean?

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What is the reason this example of an everywhere surjective function have or does not have an undefined mean?

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Suppose $f:\mathbb{R}\to\mathbb{R}$ is everywhere surjective (i.e., $f[(a,b)]=\mathbb{R}$ for all non-empty intervals $(a,b)$) where the graph of $f$ has Hausdorff dimension $2$ with zero $2$-d Hausdorff measure—i.e., the measure is defined on the Borel $\sigma$-algebra.

Here is an example.

Question: For each $c,d\in\mathbb{R}$, is the mean of $\mathsf{F}:=\left. f\right|_{(c,d)}$ (Definition $1$) undefined? If so, what is the reason? If not, then what is the reason?

Definition $\S$1. (Mean of $\mathsf{F}$)

Suppose:

  • $\dim_{\text{H}}(\cdot)$ is the Hausdorff dimension
  • $\mathcal{H}^{\dim_{\text{H}}(\cdot)}(\cdot)$ is the Hausdorff measure in its dimension on the Borel $\sigma$-algebra.
  • the integral of $\mathsf{F}$ is defined w.r.t the Hausdorff measure in its dimension

The expected value of $\mathsf{F}:A\to\mathbb{R}$ (i.e., $A:=(c,d)$), w.r.t. the Hausdorff measure in its dimension, is $m_{{}_{\mathsf{F}}\!}(A)$ (when it exists) where:

$$m_{{}_{{\large{\mathsf{F}}}}\!}(A)=\frac{1}{{\mathcal{H}}^{\text{dim}_{\text{H}}(A)}(A)}\int_{A}\mathsf{F}\, d{\mathcal{H}}^{\text{dim}_{\text{H}}(A)}$$
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Answer from math stack exchange (I looked up the user online and I am not sure he specializes in mathematics; therefore, take his answer with a pinch of salt):

Yes, the other user is right. The expected value is not undefined because the graph has Hausdorff dimension 2 or zero 2-D Hausdorff measure; that’s irrelevant since expectation integrates over the domain, not the graph. The real reason is that an everywhere-surjective function on every subinterval must be wildly pathological and cannot be Lebesgue-integrable, so the integral defining the expectation fails to exist. The geometry of the graph doesn’t determine integrability; it’s the function’s behavior as a measurable function on (c,d) that matters.

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Unless we're missing very important context, the statement of the user you quoted is patently incorre... (4 comments)
Unless we're missing very important context, the statement of the user you quoted is patently incorre...
clemens‭ wrote 7 months ago

Unless we're missing very important context, the statement of the user you quoted is patently incorrect "that an everywhere-surjective function on every subinterval must be wildly pathological and cannot be Lebesgue-integrable, so the integral defining the expectation fails to exist". Look up, e.g. Conway's tredecimal function which is everywhere surjective and yet clearly has integral 0 everywhere.

bharathk98‭ wrote 7 months ago

Thank you for checking. I will delete this one.

Is the other answer correct?

clemens‭ wrote 7 months ago · edited 7 months ago

I am not sure, although the user seems to know what he's talking about. Maybe when I look at the referenced paper I can tell. I did not previously realize that there exist functions whose graphs have a Hausdorff dimension of 2; it sounds interesting.

bharathk98‭ wrote 7 months ago

I know you’re busy…

How long will it take to check the other answer?