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This suggested edit was approved and applied to the post about 3 years ago by TextKit‭.

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If $n = xm$ and $n \rightarrow \infty$, then $m \rightarrow \infty$?
  • Did Stewart prove the result in green, himself or as an exercise, in *Calculus Early Transcendentals* or the normal version *Calculus*?
  • I attempted the proof, but I got nonplussed. $\infty = \lim\limits_{n ightarrow \infty} n = \lim\limits_{n ightarrow \infty} xm $. Now what? The limit is for $n$, but my variables are $xm$.
  • >56. Show that $\lim\limits_{n \rightarrow \infty} (1 + \dfrac xn)^n = e^x$ for any $x > 0$.
  • >[![enter image description here][1]][1]
  • James Stewart, *Calculus Early Transcendentals* 7 ed 2011. p. 223.
  • By the way, if I was writing the solution, I would've started with the game plan: rewriting $(1 + x/n)$ in the form $(1 + 1/n)^n$ in order to apply $e = \lim\limits_{x ightarrow \infty} (1 + 1/x)^x$. It's superfluous to change variable to $m$. Just rewrite $(1 + x/n)$ as $(1 + \dfrac{1}{\frac nx}).$
  • But if you craved change of variable, I would have commenced with defining $\dfrac xn$ as $\dfrac 1 m$, which is more intuitive than "let $m = n/x$".
  • [1]: https://i.stack.imgur.com/WYuLX.jpg
  • Did Stewart prove the titular result, also underlined in green in the image below, either by himself or as an exercise, in *Calculus Early Transcendentals* or in the normal version *Calculus*?
  • I attempted the proof, but I got nonplussed. $\infty = \lim\limits_{n ightarrow \infty} n = \lim\limits_{n ightarrow \infty} xm $. Now what? The limit is for $n$, but my variables are $xm$.
  • >56. Show that $\lim\limits_{n \rightarrow \infty} (1 + \dfrac xn)^n = e^x$ for any $x > 0$.
  • >[![James Stewart, *Calculus Early Transcendentals* 7 ed 2011. p. 223.][1]][1]
  • >
  • > *Transcription of image follows below:*
  • > **56.** Let $m = n/x$. Then $n = xm$, and as $n \to \infty$, $m \to \infty$.
  • >
  • > Therefore, $\displaystyle \lim_{n \to \infty} \left( 1 + \frac{x}{n} \right)^n = \lim_{m \to \infty} \left( 1 + \frac{1}{m} \right)^{mx} = \left[ \lim_{m \to \infty} \left( 1 + \frac{1}{m} \right)^m \right]^x = e^x$ by Equation 6.
  • >
  • > <sup>James Stewart, *Calculus Early Transcendentals*, 7 ed. (2011) p. 223.</sup>
  • By the way, if I was writing the solution, I would've started with the game plan: rewriting $(1 + x/n)$ in the form $(1 + 1/n)^n$ in order to apply $e = \lim\limits_{x ightarrow \infty} (1 + 1/x)^x$. It's superfluous to change variable to $m$. Just rewrite $(1 + x/n)$ as $\left(1 + \dfrac{1}{\frac nx}\right).$
  • But if you craved change of variable, I would have commenced with defining $\dfrac xn$ as $\dfrac 1 m$, which is more intuitive than "let $m = n/x$".
  • [1]: https://i.stack.imgur.com/WYuLX.jpg

Suggested about 3 years ago by The Amplitwist‭